class QJSValueIterator

The QJSValueIterator class provides a Java-style iterator for QJSValue . More

Synopsis

Methods

Note

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Detailed Description

Warning

This section contains snippets that were automatically translated from C++ to Python and may contain errors.

The QJSValueIterator constructor takes a QJSValue as argument. After construction, the iterator is located at the very beginning of the sequence of properties. Here’s how to iterate over all the properties of a QJSValue :

object = QJSValue()
...
it = QJSValueIterator(object)
while it.hasNext():
    it.next()
    print(it.name(), ": ", it.value().toString())

The next() advances the iterator. The name() and value() functions return the name and value of the last item that was jumped over.

Note that QJSValueIterator only iterates over the QJSValue ‘s own properties; i.e. it does not follow the prototype chain. You can use a loop like this to follow the prototype chain:

obj = ... # the object to iterate over
while obj.isObject():
    it = QJSValueIterator(obj)
    while it.hasNext():
        it.next()
        print(it.name())

    obj = obj.prototype()

See also

property()

__init__(value)
Parameters:

valueQJSValue

Constructs an iterator for traversing object. The iterator is set to be at the front of the sequence of properties (before the first property).

hasNext()
Return type:

bool

Returns true if there is at least one item ahead of the iterator (i.e. the iterator is not at the back of the property sequence); otherwise returns false.

See also

next()

name()
Return type:

str

Returns the name of the last property that was jumped over using next() .

See also

value()

next()
Return type:

bool

Advances the iterator by one position. Returns true if there was at least one item ahead of the iterator (i.e. the iterator was not already at the back of the property sequence); otherwise returns false.

See also

hasNext() name()

value()
Return type:

QJSValue

Returns the value of the last property that was jumped over using next() .

See also

name()